Question

8. Using two new investigational ingredients, agent X (molecular weight = 1205, dissociation factor = 2.6) and agent Y (molecular weight = 756, dissociation factor = 4.2), you are preparing a solution for an experiment as follows: Agent X 5.00 g Agent Y 5.00 g NaCl 7.75 g Distilled water QS to 1000 mL What is the freezing point of this solution? How much more NaCl do you need to make it isotonic? (20 Points) bambe to our boot boo b

Answer 1

Agent 20 5 molecularr .009 mass e 2.6 omole gu 14mber (205 2.0x5.00 17 1205 Agent 21081 7s6 molecular wrcigut s.003 mass 4.2 4.2K S.90 7564 Nack 2x 7.75 17 58.44 -10003 af water mas% molality 2.6xs.00 + 4.2x.o0 2K77S (20 5 756 58.44 1 -7 0.3038 m 4T3 0.500 O.303 8 X 1846 Faeezing point 7 moles ot No euired far isotouic an solution : O3038 1 0.IS19 mot 2 .mass 8.88 9

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