Question

B eton Med Based on interviews with 95 SARS patients, researchers found that the meanincubation period was 56 days, with a standard deviation of 15.7 days. Based on this information, construct a 95% confidence Interval for the mean incubation period of the SARS Virus Interpret the interval The lower bound is days. (Round to two decimal places as needed.)

the lower bound =

and upper bound =

and upper bound!

Answer 1

ANSWER:

Given that,

Based on interviews with 95 SARS patients, reserchers found that the mean incubation period was 5.6 days, with a standard deviation of 15.7 days.Based on this information , construct a 95% confidence interval for the mean incubation period of the SARS vitus interpret the interval.

Mean = $\bar{x}$ = 5.6 days

Standard deviation = s = 15.7

sample size = n = 95

Degree of freedom = df = n-1 = 95-1 = 94

95% confidence interval:

c = 95% = 95/100 = 0.95

$\alpha$ = 1-c = 1-0.95 = 0.05

$\alpha$/2 = 0.05/2 = 0.025

Critical value = t$\alpha$/2,df = t0.025,94 = 1.985523

95% CI = $\bar{x}$ $\pm$ t$\alpha$/2,df * (s/sqrt(n))

95% CI = 5.6  $\pm$ 1.985523* (15.7/sqrt(95))

95% CI = 5.6$\pm$ 3.198252676

95% CI = ( 5.6- 3.198252676, 5.6+3.198252676)

95% CI = ( 2.401747324 , 8.798252676)

95% CI = ( 2.40 , 8.79) (Rounded to two decimal places)

lower bound = 2.40 days

upper bound = 8.79 days

----------------------------------------------------------------------The End ------------------------------------------------------------------------

If you have any doubt please ask me friend and if you are satisfied with my solution please give me thumb up.