Question

What's the correct answer for Part B magnitude? I keep getting it wrong.

Two long, parallel wires carry currents of I₁ = 3.22 A and I₂ = 4.85 A in the direction indicated in the figure below. (Choose the line running from wire 1 to wire 2 as the positive x-axis and the line running upward from wire 1 as the positive y-axis.)

(a) Find the magnitude and direction of the magnetic field at a point midway between the wires (d = 20.0 cm). CORRECT

magnitude 3.26 μT Direction: -90 from positive x axis

B). Find the magnitude and direction of the magnetic field at point P, located d = 20.0 cm above the wire carrying the 4.85-A current.

magnitude (I put 9.68 μT and that's incorrect

Direction: 76.4 degrees left of the vertical

Answer 1

b)The magnitude is, B= by (cos 135°x + sin 1359) (47x10")(3.22) -+ 27/(0.2) +(0.2) 72* 53) =1.61x10 (-x+y)T 1.61(-x+y)uT B. = Metz (-1) (41x107)(4.85 21(0.2) = 4.85*10T(-x) = 4.85uT(-x) The total magnitude is, B tota = B,+B, =-4.85x+1.619 Betail= (-4.85)’ +(1.611 = 5.114T The angle is, =180–tan -- 2151 = 180-18.36 =161.64 = 162 The direction counter clockwise 4.85