A regression between the sales (Y) and the monthly advertising expenditures (X) resulted in the following predicted regression equations:
= 10.9 + 0.23 x
One observation in the sample data set shows that one store spend $68 K in advertising with sales of $29 K . What is the predicted sales for this store?
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$ 33 K |
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$26.54 K |
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$17.57 K |
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$29.03 K |
Here, it is given that
Y =Sales
X = Monthly advertising expenditures
The regression equation is
If one store spend $68K in advertising with sales of $29K. i.e
The predicted sales for this store is

The predicted sales for this store is $26.54 K.
A regression between the sales (Y) and the monthly advertising expenditures (X) resulted in the following...
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Question 14 A regression analysis between sales (Yin $1,000) and advertising (X in dollars) resulted in the following equation Y = 30,000+ 4X. The equation implies that an: Increase of $4 in advertising is associated with an increase of $4.000 in sales Increase of $1 in advertising is associated with an increase of $4,000 in sales Increase of $1 in advertising is associated with an increase of $34.000 in sales - Previous Next → No new data to save. Last...
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Regression analysis was applied
between sales (Y in $1000) and advertising (X in $10,000), and the
following estimated regression equation was obtained
Based on the above estimated regression line if advertising is
$10,000, then the point estimated for sales (in dollars) is
a.503
b. 5030
c. 50,300
d.503,000
Ÿ=500+ 3x
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Please answer 24 and 26 only
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