Question

*Chapter 6, Section 1-CI, Exercise 011 Use the normal distribution to find a confidence interval for a proportion p given the relevant sample results. Give the best point estimate for p, the margin of error, and the confidence interval. Assume the results come from a random sample. A 99% confidence interval for p given that p = 0.36 and n = 500. Round your answer for the best point estimate to two decimal places, and your answers for the margin of error and the confidence interval to three decimal places. Best point estimate = Margin of error = L - to The 99% confidence interval is Answer *1: the absolute tolerance is +/-0.01 Answer *2: the absolute tolerance is +/-0.001 Answer *3: the absolute tolerance is +/-0.001 Answer 4: the absolute tolerance is +/-0.001 Question Attempts: 0 of 3 used

Answer 1

& Best porost estimate = sample poop = 0.36] di z score corresponds to 946 0132.576 margin error: #z, 5(1-3), 12.576 (0.36*0.69 = +0.055] 0.36-0.055 to 0-36+0.055 = 10.305 to 10.415]