Question

L College Physics <CH09 HW-9 Problem 9.31 An air-track cart with mass m1 = 0.34 kg and initial speed vo = 0.95 m/s collides with and sticks to a second cart that is at rest initially. Part A If the mass of the second cart is m2 0.50 kg, how much kinetic energy is lost as a result of the collision? Express your answer to two significant figures and include appropriate units. HA ? Value Units Previous Answers Submit Request Answer XIncorrect; Try Again; 2 attempts remaining Provide Feedback

Answer 1

mass of - air track cart : m = 0.34 kg initial speed : Vo=0.95 m/s second cart : M2 = 0.50 kg initial speed :V2 = 0 mis. - mass of After collision mass of system : m= m, fm2 - m=0.84 kg. - and let speed is "V" So wing law of conservation of momentum : m, no tm zV2 = mv ve (0.34*0.95) + (0.50 x0) — mis. 0.84 v= 0-3845 mls. + kinetic energy before collision of system! ki= // m, vo 2 + ² M2 V2² - į x 0.34 x 10.95)2 J kis 0.15 34 J

» kinetic energy after Collision :- Kf = 1/2mv² Kf = * *0.84% (0.3845)2 J R = 0.0621 J 3 loss in kinetic energy Ak : ki-kf AK = (0.1534 - 0.0621) J AK = 0.0913 J Answer SK = 0.091 J