Question

Part I: Transistor Output Characteristic Procedure: 1. Build the circuit model in PSpice as shown in Fig. 1 with Vbb = 10V, R2 = 330 k92 and R3 = 0.22 k22. R3 0.22 Vec vbь R2 Q1 10V 330k or 147k Figure 1. Circuit configuration for Transistor output characteristic testing 2. Use Ohm's Law to calculate Ib. You may estimate Vbe as 0.7 V. Ib = _ _(When R2 = 330k) In = (When R2 = 147k) 3. Run simulation. Change the value of voltage source Vec according to Table 1 and record the value of Vce and Ic. Table 1. Transistor measurement, R2 = 330 k22 Vec (V) Vce (V) T IC (mA) Ic (mA) B = Ic/Ib 0.5 1 1.5 2.5

Please only use PSpice as stated in the directions. Any other software will not be accepted. Thanks

No multisim or LTSpice.

Answer 1

Case:1

R2=330k;Vbb=10v

Ib= (Vbb-Vbe)/R2= (10-0.7)/330k = 28.28 micro A.

5.250mA < R2 0.22 28.22uA B.845V 28.22uA 5.250mA 10.000 R1 330k 888.7mV Q2N2222 10.00 -5.278mA 10v = V2 10v 28.22A 5.250mA

Vcc vce Ic(mA) Beta=lc/lb 0.5v 81.52mv 1.902mA 67.256 1v 135.2mv 3.931mA 139 1.5v462.8mV 4.715mA 166.72 955.9my 4.746mA 167.82 1.449v 4.778mA 168.95 1.942v 4.809mA 170.05 2.928v 4.872mA 172.27 5v 3.914v 4.935mA 174.5 4.9v 4.998mA 8v 16.873v 15.124mA 181.18 5.25mA 185.64

VCE vs IC characteristics Ic(mA) 10 4 6 VCE(volts)

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Case:2

R2=147k;Vbb=10v

Ib= (Vbb-Vbe)/R2= (10-0.7)/147k =63.26 micro A.

12.04mA * R2 0.22k 83.200A 7.352V 63.200A 12.04mA 10.000 WM 147k 709.5mV Q2N2222 10.000 -12. 10mA 10v = V2 10v 33.200A 12.04mA

Vcc Vce Ic(mA) Beta=lc/1b 0.0561 2.018 31.9 0.0821 4.172 65.9 0.1044 6.343 100.3 0.1302 8.499 134.3 0.1826 V 10.53 166.4 0.5745 11.03 174.3 1.5430 11.17 176.6 2.5110 11.31 178.8 3.4790 11.46 181.1 5.4160 11.75 185.7 7.352 12.04 190.3

VCE vs IC characteristics Ic(mA) 1 2 3 4 VCE(volts) 5 6 7