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In the drawing the magnetic field has a magnitude of 1.41 T, the rod has a...

In the drawing the magnetic field has a magnitude of 1.41 T, the rod has a length of 0.765 m, and the hand keeps the rod moving to the right at a constant speed of 2.17 m/s. If the current in the circuit is 0.0611 A, what is the average power being delivered to the circuit by the hand?

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Answer #1

induced emf in rod

e = BLv = 1.41* 0.765* 2.17 = 2.341 V

average power

P = ei = 2.341* 0.0611 = 0.143 W

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