How do I solve 6.57 = 2 + log [0.125]/[H3PO4]? I know the answer is supposed...

Question

Question

How do I solve 6.57 = 2 + log [0.125]/[H3PO4]? I know the answer is supposed to be [H3PO4] = 3.38X10^-6 M, but how do I get there?

PLEASE SHOW ALL STEPS

science chemistry

Answer 1

Answer #1

(e 1) -2 6-57-2

Answer 2

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