1. 2.3 mol of HBr is added to 1.0 L of 1.2 M NH3.
Mol(s) NH3 = (1.0 L)*(1.2 M) = 1.2 mol.
NH3 is a weak base and reacts with HBr (strong acid) as per the reaction below.
HBr (aq) + NH3 (aq) ------------> NH4Br (aq)
As per the stoichiometric equation above,
1 mol HBr = 1 mol NH3.
Therefore,
1.2 mol NH3 = 1.2 mol HBr.
Mol(s) of HBr left over = (2.3 – 1.2) mol = 1.1 mol.
Moreover, NH4Br is a weak acid and the solution contains 1.2 mol NH4Br as per the stoichiometric equation above.
Therefore, the major species present in the solution = NH4Br (weak acid).
Acids: HBr, NH4Br
Bases: NH3
Others: None
2. 0.2 mol KOH is added to 1.0 L of a solution containing 0.5 M each of NH3 and NH4Cl.
Mols NH3 in the solution = (1.0 L)*(0.5 M) = 0.5 mol.
Mols NH4Cl in the solution = (1.0 L)*(0.5 M) = 0.5 mol.
NH3 is a weak base while NH4Cl is a weak acid. KOH is a strong base.
The acidic and basic components in the solution react as
NH4Cl (aq) + KOH (aq) ---------> NH4OH (aq) + KCl (aq)
As per the stoichiometric equation,
1 mol NH4Cl = 1 mol KOH = 1 mol NH4OH.
NH4OH is a weak base and doesn’t react with the weak acid (NH4Cl).
Mol(s) NH4OH formed = mols KOH present = 0.2 mol.
Mol(s) NH4Cl left over = (0.5 – 0.2) mol = 0.3 mol.
Mol(s) KCl formed = 0.2 mol.
Since the solution contains excess NH3 (base), hence, the major species present in the solution at equilibrium = NH3.
Acids: NH4Cl.
Bases: NH3, NH4OH, KOH
Others: KCl
The preparations of two aqueous solutions are described in the table below. For each solution, write...
The preparations of two aqueous solutions are described in the table below. For each solution, write the chemical formulas of the major species present at equilibrium. You can leave out water itself. Write the chemical formulas of the species that will act as acids in the 'acids' row, the formulas of the species that will act as bases in the 'bases' row, and the formulas of the species that will act as neither acids nor bases in the 'other' row....
The preparations of two aqueous solutions are described in the table below. For each solution, write the chemical formulas of the major species present at equilibrium. You can leave out water itself. Write the chemical formulas of the species that will act as acids in the 'acids' row, the formulas of the species that will act as bases in the 'bases' row, and the formulas of the species that will act as neither acids nor bases in the 'other' row....
The preparations of two aqueous solutions are described in the table below. For each solution, write the chemical formulas of the major species present at equilibrium. You can leave out water itself. Write the chemical formulas of the species that will act as acids in the 'acids' row, the formulas of the species that will act as bases in the 'bases' row, and the formulas of the species that will act as neither acids nor bases in the 'other' row....
The preparations of two aqueous solutions are described in the table below. For each solution, write the chemical formulas of the major species present at equilibrium. You can leave out water itself. Write the chemical formulas of the species that will act as acids in the 'acids' row, the formulas of the species that will act as bases in the 'bases' row, and the formulas of the species that will act as neither acids nor bases in the 'other row....
The preparations of two aqueous solutions are described in the table below. For each solution, write the chemical formulas of the major species present at equilibrium. You can leave out water itself. Write the chemical formulas of the species that will act as acids in the 'acids' row, the formulas of the species that will act as bases in the 'bases' row, and the formulas of the species that will act as neither acids nor bases in the 'other' row....
The preparations of two aqueous solutions are described in the
table below. For each solution, write the chemical formulas of the
major species present at
equilibrium.
You can leave out water itself. Write the chemical formulas of
the species that will act as acids in the 'acids' row, the formulas
of the species that will act as bases in the 'bases' row, and the
formulas of the species that will act as neither acids nor bases in
the 'other' row....
The preparations of two aqueous solutions are described in the table below. For each solution, write the chemical formulas of the major species present at equilibrium. You can leave out water itself. Write the chemical formulas of the species that will act as acids in the 'acids' row, the formulas of the species that will act as bases in the 'bases' row, and the formulas of the species that will act as neither acids nor bases in the 'other' row....
The preparations of two aqueous solutions are described in the table below. For each solution, write the chemical formulas of the major species present at equilibrium. You can leave out water itself. Write the chemical formulas of the species that will act as acids in the 'acids' row, the formulas of the species that will act as bases in the 'bases' row, and the formulas of the species that will act as neither acids nor bases in the 'other' row....
The preparations of two aqueous solutions are described in the table below. For each solution, write the chemical formulas of the major species present at equilibrium. You can leave out water itself. Write the chemical formulas of the species that will act as acids in the 'acids' row, the formulas of the species that will act as bases in the 'bases' row, and the formulas of the species that will act as neither acids nor bases in the 'other' row....
The preparations of two aqueous solutions are described in the table below. For each solution, write the chemical formulas of the major species present at equilibrium. You can leave out water itself. Write the chemical formulas of the species that will act as acids in the 'acids' row, the formulas of the species that will act as bases in the 'bases' row, and the formulas of the species that will act as neither acids nor bases in the 'other' row....