Question

In Python

Use a for-loop to create a variable called A_99, where every element is the product of the two indices from 0 to 9 e.g. A_99[3,2]=6 and A_99[4,4]=16.

a. time your script using %%time

b. Calculate the mean of A_99

c. Calculate the standard deviation of A_99

Answer 1

Thanks for the question, here is the code in python.

Refer the code screenshot for indentation and output.

Let me know for any help or questions.

thank You !

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from datetime import datetime

A_99 = []

for row in range(10):

for col in range(10):

A_99.append(row * col)

total_sum = sum(A_99)

total_count = len(A_99)

mean = total_sum / total_count

print(datetime.now())

print('Mean: {:.4f}'.format(mean))

square_sum = 0

for item in A_99:

square_sum += (item - mean) ** 2

square_sum /= total_count

print('Standard Deviation: {:.4f}'.format(square_sum ** 0.5))

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2020-01-30 10:48:54.212492 Mean: 20.2500 Standard deviation: 20.0546 main.py saved 1 from datetime import datetime 2 A_99 = [] 3 for row in range(10): for col in range(10): A_99.append(row * col) #no 7 8 total total_sum = sum(A_99) total_count = len(A_99) mean = total_sum / total_count print(datetime.now ) print('Mean: {:.4f}'.format(mean)) 10 14 15 16 17 18 19 square_sum = 0 for item in A_99:| square_sum += (item - mean) ** 2 square_sum /= total_count print('Standard Deviation: {:.4f}'.format(square_sum ** 0.5))