o A package has 8 lightbulbs. How many ways can we select 5 if the order...

Question

Question

o A package has 8 lightbulbs. How many ways can we select 5 if the order doesnt matter? cs = 8! (8-5)!57 - If ce are broken,

math Statistics-And-Probability

Answer 1

Answer #1

A package has 8 lights bulbs.

No of ways we can select 5 bulbs = $\binom{8}{5}$ = 8! / ((8-5)! * 5! ) = 56 ways

In this problem, 6 lights bulbs are broken. Then only 2 light bulbs are in working process.

we want to find the probability that 5 bulbs are broken that is

P ( 5 bulbs are broken ) = $(5)$ / $\binom{8}{5 }$

=6 / 56

=0.107

for further query please comment below.thank you

Answer 2

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