Question

2. Determine the following information about each value in a list of positive integers. Is the value a multiple of 7, 11, or 13? a. b. Is the sum of the digits odd or even? (parameter output returns 0 for even, 1 for odd) Is the value a prime number? (parameter output returns 0 nonprime, 1 for prime) c. You should write three functions: 1)input, 2) processing, 3)output 1) Input wil have one output parameter of type int stating the number of input items to process. Processing should have one input parameter stating the number of items to process, three 2) 3) output parameters to answer the above three questions Output will have 3 input parameters to display the results.

C+ using pointers

Answer 1

#include <iostream> using namespace std; int is_multiple (int num) / checking multiple of if (num% 7.0 ) return7 else if(num% 11 ) return 11: else if(num% 13-0) return 13; else return int is sum even odd (int num// checkina if sum of digits is even or odd // if even return 0 or if odd return int sum-0; while (num!-0) sum+-nums10: num/-10: if ( sum%2--0 ) return 0; else return 1;

int is_prime (int num) // checking if number is prime // if prime return 1 or if non prime return if (num(#1) return 0; int flagl: for (int i-2:i<num/2:i++) if (numi0) flag 0; break return flag: void input (int *num) // taking number of input cout<<"Enter number of items to process cin>num;

void output (int num, int mul, int sum, int prime) / displaying the result coutくくnum<<" is :"くくendl ; cout<<"Not a multiple of 7,11,or 13."<<endl; cout<<"Multiple of "<<mul<<endl: cout<<"Sum of the digits is even."<<endl; cout<<"sum of the digits is odd. "<<endl ; coutくく"Value is a prime number."くくendl ; cout<<"Value is a non prime number."<cendl else if (sum 0) else if (prime-i) else void processing (int num, int *mul, int sum, int prime) mul-is multiple (num); *sum-is sum even odd (num); k prime=isprime (num) ; -

/ driving progran int main int main () int ary[]={10, 11,7,13,15); int num, mul, sum,prime: input (&num) for ( int i=0; ǐくnun: i++) processing (aryli], &mul, &sum, &prime) output (aryli],mul, sum,prime) cout<<endl return 0;

Enter number of items to process :5 10 is: Not a multiple of 7,11,or 13. Sum of the digits is odd Value is a non prime number. 11 is Multiple of 11 Sum of the digits is even. Value is a prime number 7 is Multiple of 7 Sum of the digits is odd Value is a prime number 13 is Multiple of 13 Sum of the digits is even. Value is a prime number 15 is Not a multiple of 7,11,or 13. Sum of the digits is even. Value is a non prime number. Process returned e (0xe) execution time 1.709 s Press any key to continue.