Hey, I am telling the output along with the reason for that output-
1)
a=99.98
if a+0.01>=100:
print('A')
elif a+0.02>=100:
print('B')
print('C')
else:
print('D')
print('E')
So, the output is-
B
C
E
This is because a=99.98, if we add 0.01 then, it is less than 100,
so it will not enter the if condition, so, it will move to eilf
condition where in a+0.02=100, hence , it goes inside the elif
condition and print B and C.
After that, E gets printed as it is outside if-else .
********************************************************************************************************************************
2)
x=6
if x%2==0:
print("x is even")
else:
print("x is odd")
Output is-
x is even
This is because 6%2==0, so it goes inside the if condition and print ' x is even'.It does not go in else condition.
****************************************************************************************************************************
3)
Hey, here values for number1, number2, number3 and number4 are not mentioned, so I'm assuming by myself.
Let, number1=5
number2=20
number3=10.0
number4=5.0
number1 and number2 are int,
number3 and number4 are float
number1=5 number2=20 number3=10.0 number4=5.0 value2=number1//number2 print(value2) value2=number1/number2 print(value2) value3=number4/number3 print(value3) number1=number1+number1 number2=number1*number1 number1=number1+number2 print(number1, number2) number3=number3+number4 number4=number4*2 number3=number3+number4 print(number3,number4)
Output is-
0
0.25
0.5
110 100
25.0 10.0
Initially,
number1=5
number2=20
number3=10.0
number4=5.0
1) value2=5//20=0 (gives floor result)
2) value2=5/20=0.25 (gives actual result)
3) value3=5.0/10.0=0.5(float)
4) number1=number1+number1=5+5=10
number2=number1*number1=100
number1=number1+number2=10+100=110
5) number3=number3+number4=15.0
number4=number4*2=5.0*2=10.0
number3=number3+number4=10.0+15.0=25.0
Question 17 (3 points) Predict the output of the following code segment: a = 99.98 if...
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