Question

Can you help me with these transportation problems please?I  don't have many questions. I will rate.

Answer 1

3.

Calculate the speed of the vehicle (V) using the formula: 210n, (1-i Here, r is radius of wheel, n, is speed of the engine, i is drive axle slippage, and ε. overall gear reduction ratio Substitute 15 inch for r, 3,000 rev/min for n.. 3.5% for , and 3.5 for 1min 60 s 3.5 100 3,000rev/min x 12in 3.5 V -108.3ft/s Thus, the speed of the vehicle is 108.3ft/s Calculate the coefficient of rolling resistance (f) using the relation: In =0.01| 1+-- 147 Substitute 108.3 ft/s for V 147 0.017 Thus, the coefficient of rolling resistance is 0.0117 Calculate the rolling resistance (Rusing the formula Here, Wis weight of the vehicle Substitute 0.017 for f, and 2,500 lb for W R, -0.017x2500 R 43.4lb Thus, the rolling resistance is 43.4 1b

Calculate the aerodynamic resistance (R) using the formula: Here, p is the density of air, Cp is the coefficient of aerodynamic drag, and A, is the frontal area of the vehicle Substitute 0.002378 slugs/ft for p, 0.35 for Cp, 21ft for A,, and 108.3 ft/s for V 0.002378 R20.35x21x 108.3) R2 102.5lb Thus, the aerodynamic resistance is 102.5 lb Calculate the engine-generated tractive effort (F) using the formula: Here, M, is the engine torque and nd is the drivetrain efficiency Substitute 150 ft-lb for M,, 3.5 for s, 0.9 for nd, and 15 inch for r: 150 x3.5x 0.9 15 12 F 3781b Thus, the engine-generated tractive effort is 378 11b Consider that the available tractive effort (F) is the engine-generated tractive effort F., (F-F) Thus, the available tractive effort is 378 lb Calculate the acceleration mass factor using the relation: -1.04+0.0025e) Substitute 3.5 for e, Y 1.04+0.0025(3.5) 1.07

Thus, the acceleration mass factor is 1.07 Calculate the maximum acceleration (a) using the formula: Here, Σ R is the summation of resistances and m is mass of vehicle. Substitute 378 İb for F, (43.41b +102.51 b) for y R , 1.07 for Ym , and 2,5001b form: 378-(43.4lb+102.51b) 锆: (1.07 25001bx Islug 32.21b Thus, the maximum acceleration of the car is 2.79ft/s