Question

1.) How many moles of calcium metal react with 5.00 mol of hydrochloric acid? ____Ca(s) + HCI(aq)----- _____CaCI2(aq) + _____H2(g) 2.) How many grams of AgCI, silver chloride, are produced from 25.0 mol of AgNO3, silver nitrate? ____AgNO3 + ____BaCI2---------------    _____AgCI + _____Ba(NO3)2

Answer 1

Balanced equation 1Ca_(s) + 2 HCl_(aq) rightarrow 1 CaCl_2_9aq) + 1 H_2 (g) 1 mole 2 mole 2.5 mole 5 mole From the above balanced equation 1 mole calcium 2 moles of HCl where as 5 moles of HCl with 2.5 moles as calcium A: = 2.5 moles as Ca Balanced equation 2 Ag NO_3 + BaCl_2 rightarrow 2AgCl + Ba(NO_3)_3 2 moles Rightarrow 25.0 moles of AgNO_3 produces 25.5 moles of AgCl the molar mass of Ag Cl is 143.32 g/mole Therefore mass of Ag Cl formed = 25.0 times 143.32 g/mole = 3583 grams Therefore mass of Ag Cl formed = 3.58 times 10^3 grams.