Question

wg to the next question prevents changes to this answer Question de 25 Question 8 6 points Save As "Decibels of sound were recorded at the airport. The results are 110 95 100 115 105 110 120 110 115 105 90 95 105 110 100 115 105 120 95 110 manngrouped b histogram Form relative and cumulative frequency tables for the data T T T Arial - 3112 T. . . y the D a 2:44 PM о не е @ A O ENG

Answer 1

Given observations

110 95 100 115 105 110 120 110 115 105 90 95 105 110 100 115 105 120 95 110

The histogram for the observations is as below

We have divided the observations into width of 5 each and then calcuated the frequency.

Histogram is usuallly done on the bins, not on the individual values

Sounds in Decibels Frequency Histogram for Sounds in Decibels Bin 90-94 95-99 100-104 105-109 110-114 115-119 Frequency 100 100 105 105 105 105 110 >120 2 90-94 95-99 100-104 105-109 110-114 115-119 >120 Bin 110 110 110 110 115 115 115 120 120

The table for the frequency is as follows

Sound in Decibels	Frequency
90	1
95	3
100	2
105	4
110	5
115	3
120	2
	$\sum$frequency = 20

Relative frequency for spefic sound in decibles = Frequency of that sound in decibels / $\sum$ frequency

The values for the relative frequencies are in the below table

Sound in Decibels	Frequency	Relative Frequency
90	1	1/20 = 5%
95	3	3/20 = 15%
100	2	2/20 = 10%
105	4	4/20 = 20%
110	5	5/20 = 25%
115	3	3/20 = 15%
120	2	2/20 = 10%
	$\sum$frequency = 20	$\sum$Relative frequency = 100%