Question

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The percent of persons (ages five and older) in each state who speak a language at home other than English is approximately exponentially distributed with a mean of 5.1. a. The lambda of this distribution is b. The probability that the percent is larger than 3.94 is P(x23.94) - KOMME c. The probability that the percent is less than 8.3 is P(x 58.3) d. The probability that the percent is between 2.1 and 6.1 is P(2.1sx561)-

Answer 1

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solutions from the given Information. Here, other persons who speak het x be the percentage of languages - follows exponential distribution with mean = 5.1 x 5.1 n=1 = 0.1960 5.] => 0.196 is/0.1960 The lambda of distribution P(x= 3.94 = 1-plx <3.94). -3.94/5.1 - 1 - f (3.94) (or & 0.4618 10.4618 © PLX 38.3) - F (8.3) 10.8035 l-e - 0.8035 @ P(211 = x 56.1) = P(x56. 1) - P(xs 2.1). - f (6.1) – f (2.1) (1-6-6.1/5.1)-(1-0 2-1/5.1) - 10.36011