By Stokes theorem, we have

where
is the boundary of
. Since
has parametrization
, its boundary is
![\{(\cos\theta,\sin\theta,0):\theta\in [0,2\pi]\}](http://img.homeworklib.com/questions/27084fe0-aa0b-11ea-be58-8fcfeb4dca21.png?x-oss-process=image/resize,w_560)
Thus,

Let
so that
; then

Thus,

4. Let n be the outward unit normal vector field of the surface Sirr, ) -...
(a) Find the flux of the vector field F=yi-xjtk across the surface σ which is 4. x2 +y2 and below z the portion of z 4 and is oriented by the outward normal. _t7г (b) Use Stokes' Theorem to evaluate the line integral of J F.dr of F--уз ì_x3 j+(x+z)k where C is the clockwise path along the triangle with vertices (0,0,0). (1.0,0)and (1.i.o) aong the thiangle with(i) t)
(a) Find the flux of the vector field F=yi-xjtk across the...
Let S be the sphere r2 + y2 + z2-k2 oriented outward and let F be the vector field (r, y, 2)/(a2 +y2 +2/2. Find (i) the normal vector field n on S (ii) the normal component of F on S and (ii) the flux of F across S
Let S be the sphere r2 + y2 + z2-k2 oriented outward and let F be the vector field (r, y, 2)/(a2 +y2 +2/2. Find (i) the normal vector field n...
(14 points) Let F be the radial vector field Ft(z, y, z) =zi+w+sk And S be the surface of the cone shown at right parameterized by G(r,)-(rcos(0),r sin(0),6-3r) Write the integral F dS using an outward pointing normal in dS terms r and θ. This cone has an open bottom. . The integrand must be fully simplified » Do not evaluate the integral
(14 points) Let F be the radial vector field Ft(z, y, z) =zi+w+sk And S be the...
Let F(r, y, z)(z4+ 5y3)i + (y2 surface of the solid octant of the sphere x2+yj2 + 22 = 9 for x> 0, y> 0 and z> 0 )j+ (3z + 7)k be the velocity field of a fluid. Let B be the Determine the flux of F through B in the direction of the outward unit normal
Let F(r, y, z)(z4+ 5y3)i + (y2 surface of the solid octant of the sphere x2+yj2 + 22 = 9 for x>...
c. Let F : R³ → R³ be a vector field on R, given by the following function F(x, y, 2) = (x2)i + (y2)J + (xy)k. Calculate the flux of the field across the surface of the hemisphere, : [0, 1] × [0, 2x] → R³, where parametrized by the following function Þ(r, 0) = (r cos 0)i + (r sin 0) + (1 – 1²)!/2 k.
(20) Let S be the sphere x2 + y2 + x2 = 4 with outward normal vector. Let F(x, y, z) = (2-3 + tan-'(yz), ex2+2 + y3, cosh(xy) + 23). Use the Divergence Theorem to find the flux of Ě out of S.
Sle Evaluate the surface integral F.ds for the given vector field F and the oriented surface S. In other words, find the flux of F across S. For closed surfaces, use the positive (outward) orientation. F(x, y, z) = x2 i + y2 j + z2 k S is the boundary of the solid half-cylinder OSZS25 - y2,0 5x54 250 x
(1 point) Let S be the part of the plane z 4 y which lies in the first octant, oriented upward. Evaluate the flux integral of the vector field F 2i + j + 3k across the surface S (with N being the unit upward vector normal to the plane). B.I 48 C. I 72 E. 1 24
(1 point) Let S be the part of the plane z 4 y which lies in the first octant, oriented upward. Evaluate...
Evaluate the surface integral S F · dS for the given vector field F and the oriented surface S. In other words, find the flux of F across S. For closed surfaces, use the positive (outward) orientation. F(x, y, z) = x i − z j + y k S is the part of the sphere x2 + y2 + z2 = 36 in the first octant, with orientation toward the origin
Evaluate the surface integral | Fds for the given vector field F and the oriented surface S. In other words, find the flux of F across S. For closed surfaces, use the positive (outward) orientation. JJS F(x, y, z) = xi - z j + y k S is the part of the sphere x2 + y2 + z2 = 49 in the first octant, with orientation toward the origin