Question

11. A home schooled scientist wants to make a 2.0 F capacitor. She has lots of thin foil and a dielectric material 6.0 X 10 - m thick, with dielectric constant equal to 1300. The dielectric material has dielectric strength 300000 V/m, so if it was one meter thick, it could withstand 300000 Volts applied across it before it broke down. a) What total foil area is needed? Recall, a cap has two plates. b) What is the maximum voltage that may be applied across her finished cap? c) What is the maximum energy that can be stored in the finished cap?

Answer 1

According to the condition given in the question, we have C = 2.0MF * = 6xiom thickness. K = 1300 a) The Total foil area needed is c = KEA -12 2 = 1300 X 8,8X10 XA 6 X10-5, A = 10425,5m? So the Total area needed can be 2 A = 2x10425.5 m2 20851,07 m2

B) Now let us find out for the maximum voltage c=KE A d ckness = 6x10 m voltage = 300000 x 6x10-5 518 V Thickness of foil is given. so, we multiplied with volts with the thickness.

c) Now let us calculate for the maximum Energy stored.. Energy = €2x Volume - * * 8,8 x70\x (3x103) x 10425.5 X 6X10 = 0.249 I. maximum Energy that can be stored = 0249 1 ?