You distilled 100 mL of 40:60 ethanol:water, and collected 20 mL of pure azeotrope. What is...
You distilled 100 mL of 40:60 ethanol:water, and collected 20 mL of pure azeotrope. What is the percent recovery of ethanol?
Homework Answers
Before we answer this question we first need to know what is azeotrope
The azeotrope is a mixture of two liquids which boil at the same temperatures and ethanol and water is it's example
They boil together when mixed and boiled
It has ethanol 95% and water 5%
So from our 20 ml azeotrope ethanol will be
20× (95/100)
= 19 ml
As we know the ethanol at the beginning is 40 ml
So the percent recovery will be
(19/40) × 100
= 47.5%
I hope this helps. If you have any query or want more detailed explanation, feel free to ask in the comments section below.
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