Question

IReview Part A A small charged bead has a mass of 3.3 g. It is held in a uniform electric field E = (200,000 N/C, up). When the bead is released, it accelerates upward with an acceleration of 24 m/s2. What is the charge on the bead? Express your answer with the appropriate units. ? -μΑ Value Units q = Request Answer Submit Return to Assignment Provide Feedback

Answer 1

Consider the bead

Net Force=Mass*acceleration

$F_{e}-W=ma$, where F_e is force due to electric field and W is the weight of the bead.

and Electric Force, $F_{e}=Eq$

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$Eq-mg=ma$

$200000N/C*q-0.0033kg*9.81m/s^{2}=0.0033kg*24m/s^{2}$

$200000*q-0.0033*9.81=0.0033*24$

$200000*q=0.0033*24+0.0033*9.81$

$200000*q=0.111573$

$q=\frac{0.111573}{200000}$

$q=5.57865*10^{-7}C$

ANSWER: ${\color{Red} q=0.557865\mu C}$

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