Homework Answers
Answer
0.60M/s
Explanation
For a general reaction
aA + bB ------> cC + dD
-(1/a)d[A]/dt =- (1/b)d[B]/dt= (1/c)d[C]/dt = (1/d)d[D]/dt
Therefore, for the given reaction
4NH3(g) + 5O2(g) -------> 4NO(g) + 6H2O(g)
-(1/4)d[NH3]/dt = -(1/5)d[O2]/dt = (1/4)d[NO]/dt = (1/6)d[H2O]/dt
(1/5) × rate of disappearence of O2 = (1/4) × rate of appearence of NO
Therefore,
rate of appearence of NO = (4/5) × rate of disappearence of O2
rate of appearence of NO = (4/5) × 0.75M/s
rate of appearence of NO = 0.60M/s
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