C 4 H 9 , 114.21 g/mol Express your answer as a chemical formula.
given :
Emperical formula = C4H9
molar mass = 114.21 g/mol
mass of emperical formula = 4 x 12 + 9 x 1
= 57 g/mol
ratio n = molar mass / emperical formula mass
= 114.21 / 57
= 2.00
Molecular formula = n x Emperical formula
= 2 x C4H9
Molecular formula = C8H18
Empirical formula C2H4O, molar mass = 132.0 g/mol Express your answer as a chemical formula.
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