how many carbons?
A. 2C3H8
B. CH(CH3)3
C. 4CH3(CH2)3CO2H
A. For one molecule 3 carbons
For two molecules 6 carbons
2C3H8 = 6 carbons
B. CH(CH3)3 = 4 carbons
C. 4 CH3(CH2)3COOH = 4 x 5 = 20 carbons
For one molecule 5 carbons for 4 molecules 4 × 5 = 20 carbons
8. How many chiral carbons are present for the following molecule? CH3 HO–CH2-CH2-C-CH=CH-CH3 NH2 a. 4 b. 3 c. 2 d. 1 e. none
name the compounds
b. CH3 CH3-CH2-CH-CH-CECH CH2-CH3 CH3 CH=C-C-CH3 CH2-CH2-CH3 1 CH3 - CH2 - CH = CH-CH3
5. Which is a protic solvent? A) CCIA B) HCC13 C) CH3(CH2)4CH3 D) CH3CH2OCH2CH3 E) CH3CH2OH
Name each of the following. a CH3 CH3 -CH-CH-CH-CH2-CH3 qt om CH3 CH3 b. CH3-CH-CH-CH-CH-CH2-CH3 III CH3 CH3 CH3 CH3 c. CH CH3-CH2-C-CH2-CH3 CH d. CH2-CH CH3-CH2 qhech CH-CH2-CH2-CH2-CH-CH b. CH3-CH=CH-CH-CH-CH2-CH3 CH3 CH3 CH3 CH3 CH3 CH3-CH2-C-CH2-CH3 сна d. CH2-CH CH3-CH2 quhe-Com convenie CH-CH2-CH2-CH2-CH-CHE CH2-CH 9 item attempts remaining ot Try Another Version Submit Answer
My Home [Ref Name each of the following alkenes. a. CH2=CH-CH2-CH2-CH3 b. CH2CH3 CH3 -CH2-CH=C-CH3 c. CH3 CH.CH2CH-CH2-CH=C-CH3 CH3 Submit Answer Try Another Version 9 item attei
Write the correct name for each compound below. H3C-CH3: H3C-CH2-CH2-CH2-CH2-CH2-CH2-CH=CH2: H-C≡C-H: H-C-(CH3)3: H3C-CH=CH-CH3:
Which of the following can exist in enantiomers? a. b. CH3 CH3-CH;-CH2-C-CH; CH3-CH2-CEC-CH, C. d. all of these choices CH3-CH-C-CHE -8-сон, CH,-8-3-CH, спесне: -он, 10. What type of compound is the second product in the reaction shown below? CH-0-2-CH, OCH & CHOCH, H,CH, +3 NaOH + CH-OH + CH-OH CH -0-C-(CH2)16CH, a, fatty acid salt b. ester CH-OH c. alcohol d. fatty acid
Give common names: a. C CHZ CH-CH3 OH ?. d. CH3 CH2-0-CH2-CH2-CH2-CH3 b. 0 CH2 CH CH2 CH2 CH3 CH2CH3 2 e. CH3 N CH2-CH2-CH3
CH3-CH2-CH2-CH2-CH=CH-CH3 a) alkane b) alkene c) alkyne d) saturated hydrocarbon 2
Classify each of the following organic reactions. Addition CH3-CH2-CH-CH3 – CH3-CH2-CH=CH2 + HCI CH3-C-O-CH3 + CH3-NH-CH3-C-NH-CH3 + CH2-OH CH3-CH2-CH2-OH + HBr -- CH3-CH2-CH2-Br + H20 Elimination OH CH2-CH + HCN – CH3-CH-CN CH3-CH=CH-CH3 + HBr + CH3-CH-CH2-CH3 Br Substitution CH3-CH2-CH2-CH3 + Cl2 → CH-CH2-CH2-CH3 + HCI СІ CH3-CH=CH-CH3 + Cl2 - CH3-CH-CH-CH3 CICI Reset