here,
15)
the force applied , F = 38 N
the total weight of boat one , W1 = 105 N
mass of boat 1 , m1 = W1 /g = 10.7 kg
the total weight of boat second , W2 = 175 N
mass of boat 2 , m2 = W2 /g = 17.84 kg
the acceleration of 1 , a1 = - F /m1
a1 = - 38 / 10.7 m/s^2 = - 3.55 m/s^2
the acceleration of 2 , a2 = F /m2
a2 = 38 / 17.84 m/s^2 = 2.13 m/s^2
time interval , t = 0.5 s
the separation , s = 0 + 0.5 * ( a2 - a1) * t^2
s = 0 + 0.5 * (2.13 - (-3.55)) * 0.5^2
s = 0.71 m
the seperation between the two boats is c) 0.71 m
Two boat, meet on . lake. Penn-l pushes on b at#2withahrinr tal free of 38 ON..rokin...