Question

Question 19 Your answer is partially correct. Try again. is a binomial with p = 0.0001. If 1000 bits are transmitted Let x denote the number of its received in error in a digital communication channel, and assume that determine the following. Round your answers to four decimal places (e.g. 98.7654). (a) P(x - 1) (b) PCX 21) (c) PCX s 2) (d) mean and variance of X. T0.0905 (b) 0.0952 UTI (c) 0.9998 (a) Mean - 10.3162 (d) Mean - 0.3162 Variance Statistical Tables a Question Attempts: 1 of 3 used SAVE FOR LATER SUBMIT AL 2 powered by MapleNet

Answer 1

Answer:

here distribution is Binomial Distribution

n = 1000, p = 0.0001

The population mean is computed as:

$\mu$ =n * p

$\mu$ =1000 * 0.0001

$\mu$ =0.1

Mean = 0.1

formula for population variance is

$\sigma^{2}$=n * p *(1−p)

$\sigma^{2}$ =1000⋅0.0001⋅0.9999

$\sigma^{2}$ =0.1

population variance= 0.1