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13. (12 pts). Consider the following electrochemical cell at 25.C: Fe(s) | Fe2+ (0.250M) I I NOs (1.25M), pH=1.85 |NO(g) (0.345 atm), 1 Pt(s) A) What is the overall chemical reaction for this cell? (Hint: Look at the front cover) B) What is E? C) Calculate el nF (o (q 4851104) D) What is the maximum electrical work obtainable from this cell? Need part b and e
radioactive isotope because, as an alkali earth metal, it will substitute for calcium in bones and teeth. Predict its decay pathway. a. a emission dy emission emission itron emission X-ray emission 2
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13)

A) Reducti on half reacti on 2NOg-(aq) + 8H+ (aq) + 6 e--> 2N0(aq) + 4H20(1) Ecathode = +0.96V Oxidation half reaction: 3Fe(s) >3Fe* (aą) +0.44V Cell reaction 3Fe(s) + 2N03-(aq) +8H+ (aq)->ЗРег+ (aq) +2NO(aq) + 4H2O(1) B) Standardcell potentia thodere 0.96V-(-0.44 V) = +1.40 V C)Cell reacti on 3Fe(s) 2NO3 (aq)8H*(aq) 3Fe* (aq) 2NO (aq) 4H20() No of moles of electrons transferredin the cell, 6 H1- 10-p- 10-185 0.014M 0.0591V, Fe* (F According toNernst equation, - NOjH* 0.0591V (0.250) (0.345) 6(125) (0.014) D)No of moles of electrons (n) transferred in the cell = 6 mol e- Free energy change of the reacti on, AG -nFEc. 2) 741 kJ Work done =-△G =-(-741 kJ) = +741 kT

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Need part b and e 13. (12 pts). Consider the following electrochemical cell at 25.C: Fe(s)...
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