![WORK DONE BY AN IDEAL GAS Ivariant of FSU Physies libl: An ideal monoatomic gas is slowly compressed at a constant pressure of 1.80 atm from 13.0 L to 3.00 L. This process is represented in the Figure as the path B to D. Heat is then added to the gas, holding the volume constant, and the pressure and the temperature are allowed to rise (line DA) until the temperature reaches its original value (TA- Ta). PART A: Calculate the total work done by the gas in the process BD [Convert to SI units]. PART B: Calculate the work done in process DA. Hint: The volume is constant during the process DA [DATA: 1 atm - 1.013 x 103 N/m2 and 1 L 103 m] 0 4610 12 14](http://img.homeworklib.com/questions/7ae87e90-aad9-11ea-9f40-81421583444a.png?x-oss-process=image/resize,w_560)
Homework Answers
1. Work done by gas during B to D:
W= PδV
W=1.8x1.013x105x(13-3)x10-3
W=18234N-M or 1.823 KJ
2.The work done is the area under the curve for the process. Because there is no area under the curve in a constant-volume process the work done by the gas is zero.
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