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In a survey, 66% of Americans said they own an answering machine. If 17 Americans are selected at random, find the probabilit

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Answer #1

p=66\%=0.66, n=17

Let q=1-p=0.34

P(x)=n_{C_{x}}(q)^{n-x}(p)^{x}

P(9)=17_{C_{9}}(0.34)^{17-9}(0.66)^{9}=24310(0.34)^{8}(0.66)^{9}=0.1032

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