Question

The shaft of the motor M turns with an angular velocity w=100(4+t) rad/s, where t is in seconds. (Figure 1) Figure < 1 of 1 > mmc 30 mm 50 mm 225 mm 40 mm м w

Answer 1

Angular relocity of motor shaft Ws = 100/4+t) = Angular velocity of Gear À Now contact relocity of Gear na contact velocity of year B [ Pitch point] :>) w x 40 = We x 225 » Was = Wax & since Gear Btc on same shaft We = WB = 40 WA How we x zo = W x 300 4 WA 225

Gear D & Now E are on same shaft = Wp = WE = 4 5 WA = 4x10014+t) Now we know that w = do de 400 14+t) dhe - do = 1.7778 (4+t) at Integrating both side we get T (1.7778) × 4 dt + 1.7778 tdt E . [7.4)* + [129784 17.7775 + 5.5556 23.333 radian

be will, rotated by 7 In 2-5 8 shaft 23.333 sadian → No. of revolution of shaft 23.333 2Ã = 3. 7135 revolution and In one revolution Wis lifted by TDE mm - 1x 50 mm Distance of W moved = 23.133 xXx 50 583 325 mm.