Item 8 In the circuit shown in (Figure 1), E = 61.0 V, R4.00 1, R2...

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Question

science physics

Answer 1

Answer #1

part F)

for the S closed

Rnet = 4 * 6/(4 + 6) + 3 = 2.4 + 3 = 5.4 Ohm

current in 6 Ohm = 61/5.4 * 4/(4 + 6)

current in 6 Ohm = 4.51 A

the current in 6 Ohm is 4.51 A

part G)

when S is open

current in 3 Ohm = V/(Req)

current in 3 Ohm = 61/(6 + 3)

current in 3 Ohm = 6.78 A

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Answer 2

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