Question

Chapter 27, Problem 036 In the figure ει = 6.08 V, ε2 = 13.2 v, R1 = 99.9 Ω, R2 = 198 Ω, and R3 = 304 Ω. One point of the circuit is grounded (V = 0). what are the (a) size and (b) direction (up or down) of the current through resistance 1, the (c) size and (d) direction (left or right) of the current through resistance 2, and the (e) size and (f) direction of the current through resistance 3? (g) What is the electric potential at point A? te, (a) Number Units (c) Number Units (e) Number Units (9) Number Units

Answer 1

Solution,

Applying Kirchhoff's laws,

6.08 - 198 I1 - (99.9)(I1 + I2) = 0

297.9I1 + 99.9 I2 = 6.08 ........(1)

304 I2 + 99.9 I2 + 99.9 I1 = 13.2

99.9 I1 + 403.9 I2 = 13.2 ........(2)

From equation (1) and (2)

I1 = 0.01 A, I2 = 0.03 A

A)

Current = I1 + I2 = 0.04 A

B)

Downwards

C) D)

Current = I1 = 0.01 A (left to right)

E) F)

Current = I2 = 0.03 A (right to left)

G) Va = 6.08 - (198 x 0.01) = 4.1 V

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