Question

Ser CH C.H.BR Ser 10 NF: C.He 1,3-C.H2Br2

lewis structure

Answer 1

Lewis structure Page No. when we write Lewis streaptelse valence electrons of atoms are used electrons to ing electrons are indicated e- -c h electrons =4x3+8x1. Pese a molecule, we have to use the Valence shell electrone in such a way so t every atom should be octet out in Hit y duples e make Covalent bond of Co-ordinate bond. Those electrons are not used in bonding he non bonding electrons are by lone pair Electrons are indicated by dotle) of cro single bond by - line, double bond (=) lime, triple bond (= line. Atom having highest Valence should Present at the Center of molecule, other atoms are surrounded by central atom.. Carbon is always tetravalent. in organic coment a ron va das Hg (Propane) - 4 H 14 Total valence Total bonding electrone lox2= 20 electrons Nonbonding electron ezero al carbon atoms satisfying Hence no lone Pair honbonding electrone) present in loctet rule and to Hg. are duplet. - - N N -F; ShyBr B2 H a raoltet Total valence electrons - 5+2(N) +7+4E) +38 electrons Total Valence electrons = 4x2(0) + IxL (H) + 7x2 (137) Total boneling electrore = 26 electrons. - 5x2 = 10 electrons Total boneling elections Hence Alon bonding electrons 7x2 =14 cAll are single bonds) - 28-10-28 Hence non bonding electrons Hence number of lone Pair Total yalence electrons) total toneling electrons) = 26-124 = 12 electrons All atoms are octet. Hence number of lone pais electors - 126 n td :F: N. F F (b

(c) C H2382 Total valence u Hrç C-4 electrons 1 - 4X216) + 7x2(137) + 1x4 Bon 37: - 26 electrons Total bonding electrons = 7x2=14 electrong Because all are single bonds Each single bondt, share two electrons. Each double bonds () share u electrons. Each triple bonds (=x share 6 electrone Hence Non boneling electrore-26-14=12 Hence lone pair = 12/2 = 6 lone patr Ho (propene) H H -C- Hotal number of Valence Helectrons - 4x3 (6) + 1x6 =18 Total number of bonding electrons- +2 (single bond 4 174 (double bond = 18 electrore) Hence non bonding electrons - 18-18 = 0 no lone pair electrons present 13- HBO2 & 12 THE -H Total valence electrons y Bri 4x3(c) + 742 + 1x 21H IH electrony 3 = 28 (38) Total bundling electrony = 4x2 single bond It auf l electrony Number of non bonding 16 electrone 1 bond elec- - 3 M) flectoon = 28-16-12 Hence number of lone pair=126