Question

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10:46 PM Wed Oct 2 < > a AA F19 instructur... Si Mock Ex... west.cengagenow.com CH 115 Ge... Cengage Ć OWLv2... . 18%D ☺ ☺ + 0 Get Home... Online Tut... [References] Ⓡ Assignment 7 - Calorimetry 1. Specific Heat to Energy 1 pts M [Review Topics] Use the References to access important values if needed for this question. 2. Energy to Specific Heat 1 pts M 3. Specific Heat Capacity: Find T 1 pts 2req Preparation Question Question Question A sample of liquid water is heated with an electrical coil. If 928 J is added to a 14.5- gram sample and the final temperature is 35.3°C, calculate the initial temperature of the water. Answer: °C. Submit Answer Retry Entire Group 1 more group attempt remaining Progress: 2/3 groups Due Oct 2 at 11:55 PM Previous Next Finish Assignment Save and Exit Cengage Learning Cengage Technical Support

Answer 1

Heat absorbed(q) by water is calculated by the following formula

q = m × ∆T × C_s

where,

m = mass of water, 14.5g

∆T = Temperature difference , 35.3℃ - Initial temperature

C_s = specific heat capacity of water, 4.184J/g ℃

q = 928J

substituting the values

928J = 14.5g × (35.3℃ - Initial temperature) × 4.184J/g ℃

928J = 2141.58J - (60.668J/℃× Initial temperature)

Initial temperature × 60.668 J/℃ = 1213.58J

Initial temperature = 1213.58J/60.668J/℃

Initial temperature = 20.0℃