Question

Solve Example 3.2 and 3.3 only, I have posted 3.1 as a reference

Example 3.1 A robotic vehicle is exploring the surface of Mars. The stationary Mars lander is the origin of coordinates, and the surrounding surface lies in the xy-plane. The vehicle, which represents as a point, has the coordinates: x = 2.0 – 0.25t2 y = 1.0t + 0.025t3 a) Find the vehicle's coordinates and distance from the lander at t = 2.0s. b) Find the vehicle's displacement and average velocity vector for the time interval t = 0.0 s to t = 2.0 s. c) Find a general expression for the vehicle's instantaneous velocity. Express Ở at t = 2.0 s in component form, and in terms of magnitude and direction.

Answer 1

Example-3.2 0 2 - 0.25 yf+0.0254?. Vydy - 2 Vede – 0 0.25x2t : -Ost 1 + 0.025 43 42 V₂ - To Average acceleration = velocity at I = 2sec. u n tila (ang acci) y = Nely-tily - J -0.5 average acceleration - Along c = -0.582 – 0 2 – 0 Along y = (1 + 0.075 x 4) - 1 - 0.3 2 – 0 20, average acceleration = (-0.53 + 0.37 So, Components of average acceleration in 0.5 aloog -ve ne-axis and 0.3 aloog tve, .axis

(16) do -0.53 = -o:S hogy 1 + 0.025 *332 sdy - 0 +0.07524 = 0.1st : Grestantaneous acceleration - a = – 0.5 ] + (0.15x2) Î – – 0.5] + 0.30 ? 8:33.3 ;> a. 110.sy2 + (0.312 = 0.5830 Now, So, a,; = a Congo 10 = a Corar a - 0.5830x0.933 = 0.54427 m/s position of vehicle 9 = asing at t-asec. a = a final = 0.5830 x 0.3583. = 10. 2089 m 152