Question

uwith radi q and kly lons set of concentric Cylinder with a pokatiel with a potntial difference een them and an lih matcrial filling the เด pace be tween the cylinders

Answer 1

Given that the potential difference v is there at the ends of the conductor as the electrons move, they encounter some damping forces called resistance based on ohm's law (j = sigma E) we derive the resistance of the conducting material suppose the conductor has a uniform cross section s and radii a and b, and length l of the conductor the direction of E produced is same as the direction of the flow of the positive charges or current I E = v/l since the conductor has a uniform cross section J = I/s I/s = sigma E = sigma v/l we know, R = v/I = l/sigma s \r\n R = l/sigma s we have cross section area = 4 pi r^2 s = 4 pi r^2 s = 4 pi (r_2^2 - r_1^2) s = 4 pi(b_1^2 - a^2)