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l unnohm electric field. What is the magnitude of the electric field? If this charge is removed and a 5 μC charge is placed a

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Answer #1

here,

work done required , W = 800 J

potential difference , V = 40 V

let the magnitude of charge be q

W = q * V

800 = q * 40

solving for q

q = 20 C

the magnitude of charge is 20 C

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