![Exp [H₂0] (M) 1.0.212 ; 2 0.212 3 0.424 14 0.848. Initial rates) 0.0315 0.0633 WN [No] (M) 8.136 0.272 - 0.544 S ..0.544 0 .](http://img.homeworklib.com/questions/b9b14a00-b03c-11ea-8f4c-273667c95827.png?x-oss-process=image/resize,w_560)
Hydrogen gas reduces NO to N2 in the following reaction: 2H,(8) + 2NO(g) – 2H,0 (8)...
Hydrogen gas reduces NO to N2 in the following reaction: 2H2(g) + 2NO(g) + 2H20(g) +N_(8) The initial reaction rates of four mixtures of H2 and NO were measured at 1500°C with the following results: Experiment [H2lo (M) [NO] (M) Initial Rate (M/s) 1 0.212 0.136 0.0275 2 0.212 0.272 0.0553 3 0.424 0.544 0.435 0.848 0.544 1.75 4 Determine the rate constant for the reaction at 1500°C. M-xs-1
Need help with part 2
Hydrogen gas reduces NO to N2 in the following reaction: 2H2(g) +2NO(g) + 2H20(g) +N2(g) The initial reaction rates of four mixtures of Hy and NO were measured at 1500°C with the following results: Experiment (H2lo (M) [NO], (M) Initial Rate (M/s) 1 0.212 0.136 0 .0225 0.212 0.272 0.0453 0.424 0.544 0.355 0.848 10.544 1.43 V 3rd attempt Part 1 (1 point) W See Periodic Table Choose the correct rate law for the reaction...
what is the correct rate law for the reaction at 1500 C
determine the rate constant for the reaction at 1500C
Hydrogen gas reduces NO to N2 in the following reaction: 2H2 (g) +2NO(&2H20(g)N2() The initial reaction rates of four mixtures of H2 and NO were measured at 1500°C with the following results: Experiment [H2lo (M) [NOlo (M) Initial Rate (M/s) 2 3 4 0.212 0.212 0.424 0.848 0.136 0.272 0.544 0.544 0.0265 0.0533 0.419 1.68
I need help with part b which is
Determine the rate constant for the reaction at 1500°C.
The answer should be ___________ M^-x S^-1
This is a Mixe worth 1 point / You have 2 of 6 attempts remaining / There is a 396 attempt penalty 12 Question (1 point) See page 569 Hydrogen gas reduces NO to N2 in the following reaction: 2I12(g) +2NO(g211,0g)+N2g The initial reaction rates of four mixtures of H2 and NO were measured at 1500°C...
Ch. 13 NAME 1. Consider the reaction: 2NO (g)+ 2H:(g) N2(g)+ 2H O (g) At a certain temperature, the equilibrium concentrations are [NO]-0.31 M [H2]-0.16 M [N2] 0.082 M and [H:0]-4.64 M (a) Write the equilibrium expression for the reaction. (b) Determine the value of the equilibrium constant 2. The equilibrium constant Kc for the following reaction is 150.7 at 1 15°C: 12 (g) + Br2 (g) ←→ 2 IBr(g) 2.00 moles of each gas (l2, Br: and IBr) are...
HW PLZ HEP WITH BOTH
Consider the reaction 2NO(g) + 2H2(8) N2(0)+2H,00) Using standard thermodynamic data at 298K, calculate the entropy change for the surroundings when 2.06 moles of NO(e) react at standard conditions. AS surroundings J/K Consider the reaction N2(g) + 3H2(g) 2NH3(e) Using standard thermodynamic data at 298K, calculate the entropy change for the surroundings when 2.04 moles of NzC) react at standard conditions. AS surroundings SEJAK
The rate law for the reaction 2H2(g) + 2NO(g) ----> N2(g) + 2H2O(g) is rate=k[H2][NO]2. What is the rate constant at 800 degrees C when [NO] = 0.050 M and [H2] = 0.010 M and the rate of the reaction is 1.5 M/s
A proposed mechanism for the reaction 2NO(g) +2H2(g) → N2(g) + 2H2O(g): Step 1: 2NO(g) → N2O2(g) (very fast, reversible) Step 2: N2O2(g) + H2(g) → N2O(g) + H2O(g) (slow) Step 3: N2O(g) + H2(g) →N2(g) + H2O(g) (fast) What is the rate law for the overall reaction? O k[no]/2[Hz] O k[N20][H2] O k[NO]2 O k[NO]2[Hz] O k[NO]2[H212
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A proposed mechanism for the reaction 2NO(g) +2H2(g) → N2(g) + 2H2O(g): Step 1: 2NO(g) + N2O2(g) (very fast, reversible) Step 2: N2O2(g) + H2(g) N20(g) + H20(g) (slow) Step 3: N2O(g) + H2(g) →N2(g) +H2O(g) (fast) What is the rate law for the overall reaction? Ok[NO2 Ok[NO]2[H212 O k[NO]2[H2] Ok[N20][H2] k[NO]1/2[H2] 2NO(g) +Cl2 (g) → NOCI (8) Experiment concentration of NO (M) 0.09 0.045 0.045 concentration of Cl2(M) Rate (M/s) 0.01 3.40 x 10-4 8.50 x...
Initial rate data is given in the table for the following reaction. 2NO(g) +0,(g) + 2NO,(8) Experiment (NO) initia, (M) olinitial (M) Rate (M/s) 0.420 0.460 0.206 2 0.840 0.460 0.824 3 / 0.420 0.920 0.412 4 0.420 0.230 0.103 What is the rate law for the reaction? Orate = k[NO][02] Orate = k[NO]”[02] rate = k[NO] rate = k[NO]{0,12