Question

Q2: An office building of simple construction has a constant bay width of 12 m in the longitudinal direction. In the transverse direction, the column spacings are 4 m followed by 3 m. Assuming that the slab spans one-way, calculate the moments and forces required for internal longitudinal beam design. Use the following structural data, Structural members: Longitudinal beam: Transverse beam: Slab: UB 533 X 312 x 151 UB 356 x 127X33 250 mm thick RC Imposed loading General office: 2.0 kN/m2

Answer 1

. umf tl2m → - Consider internal longitudnal or - Beam AB TAYIB The hatched areas is the I KLI tributary area for that beamt 2 How load on AB - W= live load & dead load live load = 25x3 25x2 + 25x1.5=87.5 kN/m Dead load - 25x0.250x2 + 25x0.25*1.5 = 21.875kW È total load = 87.5+21.875 = 109.375 kN/m E Shear force for design 109.375 kN/m = VA= wb = 109.375*12 PA - 1656.25 kN lam Moment for Design mman will be at centre --[2m – 2 1 2 man - 375x1a Mman = won a ton, 35212-(1968.75 km) .5kNm Am