Question

Enough of a monoprotic acid is dissolved in water to produce a 0.0169 M solution. The pH of the resulting solution is 2.41. Calculate the Ka for the acid. Number

Answer 1

Acid hydrolyis reaction is Initial: Change: Equilbril n: 00169-x pH- 2.41 H,O-1-10-241 0.0169 0 0 3.89x10 [A ]-3.89x10* [HA]-0.0169-x 0.0169-3.89x10-3 1.30x102 Acidity constant expression for the reaction Ka-HA НА 3.898 10-3 x 10-3)(3.898 10-3 1.30x102 1.16x10 Hence, Ka for the acid is 1.16x10