Question

For the network of Fig. 13.8: 80 A R320 FIG. 13.8 (a) Find ly by determining the reading of an ammeter placed between points a and b. V=ZAha) = 40 for I love it natt . 202 (24) = 0.284 A Tu (2A) = 0.276A no :6.42A In=1, + Iz = 6.7IGA lur 1, 0.75A (b) Find Ryby determining the load resistor R, that must be placed between points a and b to establish I= 1/2. I = I. - Ora Ra R. I VI 6.3575 A ISNE

Answer 1

1. 42 apply KVL in loop -6 + 8 TN + MIN --IN) 2:0 - G+ 8 TN +4 IN -4 +2 IN 20 'MIN = 10 IN10: 0.7141 IL = 0.3575 litum sex 0357 s 2 SRL Y 1.642 Կ ԱՐ - 6 + 8 X0.357 + RLX0-357 + 4x03 57 - 2 X 1642-0 R : -14.1 5 0357 Ro RN 6 .212 +82 + RNlych (Norton's resistance] =RL Scanned with CamScanner