Solution –
Current population = 120,000
Water usage over last year = 2.096 * 107 m3 = 2.096 * 1010 litres
= 5,537,046,217.43 gallons
= 5537.05 million gallons
Average Daily consumption (q) = Total yearly water usage / (365)
q = 5537.05/ (365)
q = 15.17 MGD
(MGD = million gallons per day)
For determining other average flows, we use Goodrich formula
P = 180 * t-0.1
Where,
P = Factor multiplied by average daily to determine the maximum of that period.
t = time in days.
Maximum daily consumption = 1.8 * q
= 1.8 * 15.17
= 27.306 MGD
Maximum hourly consumption = 1.5 * [1.8 * q/24]
= 2.7 * (q/24)
= 1.71 MGD
Average weekly = Total yearly water usage / (52)
= 0.29 Million gallons per week
Average monthly = Total yearly water usage / (12)
= 1.26 million gallons per month
Maximum weekly consumption = 1.48 * average weekly
= 1.48 * 0.29
= 0.43 million gallons per week
Maximum monthly consumption = 1.28 * average monthly
= 1.28 * 1.26
= 1.62 million gallons per month
After 10 years, population = 142,500
By arithmetic method,
Annual increment = (142500 – 120000) / 10
= 2,200
After 10 more years,
Population will be = 142500 + 2200*10
= 164,500
After 1 year,
Population will be = 142500 + 2200
= 144,700
By geometric method,
Percentage increase = 2200 / 120000
= 1.83 % per year
After 10 years
Population will be = 142500 (1 + 0.0183)10
= 170,331
After 1 year
Population will be = 142500 (1+0.0183)
= 145,108
Increase in population in geometric method is more as compared to increase in population from arithmetic method.
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