Question

the answer in this picture is wrong !!!

190 Given A - 250 20, R 850 ft and the PI station 53+11.10, Compute the deflection angles of at even 80 ft stations. T= R tan 2 - 850 tan 25 26 D=25'20' R=ssoft T: 191.04 PI = 53+11.10 L = T RA I (850)(25 26') angles asoft. (l= 375.83 Pc = station PI-T ) 53+11.10 - 191.04 51+ 20.06 PT a station peth a 33+11.80 + 375.83 56+86.93] ? a ett / st 51+20.06 80-20.06 ( 59.94 ) 59.94 4° 2'25.214/2° 1'12.610 53+00 ( 139.94 19° 25' 58.254 14° 42'59.12 54 + 219.94 55 too 299.94 24 station 52100 80 80 14°49'31.28" (7 24' 45.64" 120°13'4.31" llo''32.46" 56+86.93 ( L.93. 229.94

Answer 1

nin A. 25'20', 25.38 R: 850 ft Stap 53+11.10 T= R tom - 250 tam 25.33 191.04 ft i la RRA - Rx850x 25.33 180 - 375.8 f i sta por Staps - T sta 5tin.10 - 19104 5311.10-19104 o 5 asta (51 +20.06) 5120.06 ista PT. Stapet Losta (51+20.06] + 375.78 2 5120.06+375.78 2 5495.84 2 stal sut 95.84) Points Stations l(disture from Deflection Angle (d, 180x8) PC 51420.06 8/2 TRR 52+00.50 १.१५ 5023²194 159.au PT 52+80.00 52+ ། 53+ 60.00 sut 40.00 2 41' you 5° 23'264 60 261 204 191.04 239.au 40 : รฯ 120 52 394 16 lo' 254 21° 33'584 250 lg' 48' 319.94 8° 5' 12.50 PT 54+ 95.84 10° 46594 375.78 12°39 sur