Question

Write a C program that accepts a phone number of the form +1(xxx)-xxx-xxxx

where x is a digit, and displays the sum of all digits in the phone number.

Answer 1

#include<stdio.h>
int main(){
char phone[20] ;
int a;
int total = 0;
printf("Enter the phone number in the form +1(xxx)-xxx-xxxx \n");
//Getting the phone number and save it in the character array
gets(phone);
//for loop is to iterate over the character array to find the total
for(a = 2; a <= 20; a++){//initial a= 2 to ignore the '+1'
switch(phone[a]){
case '1':
total = total+1;
break;
case '2':
total = total+2;
break;
case '3':
total = total+3;
break;
case '4':
total = total+4;
break;
case '5':
total = total+5;
break;
case '6':
total = total+6;
break;
case '7':
total = total+7;
break;
case '8':
total = total+8;
break;
case '9':
total = total+9;
break;
default:
total= total+0;
break;
}
}
printf("Total of the digits of the phone number is %d", total);
return 0;
}

Enter the float value in line 1, Character in the next line, integer in next line and Character in the 4th line: 1234.56 a 50 b Output in single line 1234.56 a 50 b Process returned 0 (ex0) Press any key to continue execution time 9.853 s