
please help me answer this statistic question about estimation/confidence interval
![sall ū219.30 Sa. 10:24 na 16 904.C.I. 1024 [ af te ne han] [19:30 7 toos, is so 5.05,is: 2-13 519.30 I (2:13)* •7988] 9 [19.3](http://img.homeworklib.com/questions/bfa978d0-b331-11ea-a343-c14d3149dd12.png?x-oss-process=image/resize,w_560)
please help me answer this statistic question about estimation/confidence interval Confidence interval (1 –a) 100% for...
If n < 30 and σ İs unknown, then the 100(1-α)% confidence interval for a population mean is_ 7. assuming the population is normally distributed xtra 21 1(degrees of freedom = n-2) a. 1 (degrees of freedom-n-1) c. t(degrees of freedom-n-1) 1 d. x ± te |--| (degrees of freedom n-2) 1 (degrees of freedom = n-1) If n interval when the level of confidence is 99% 8. 16, then find the number ta2 needed in the construction of a...
6. Interval estimation, z, t, and sample size Aa Aa Which of the following statements about the confidence interval for a population mean are true? Check all that apply. when σ is known, Χ Ζα/2ƠNn is a good interval approximation, provided the population is normally distributed when σ is unknown, x ta/2s Nn is a good interval approximation, provided the sample size is sufficiently large. when σ is known, X za/20, Vn is a good interval approximation, provided the sample...
True or False? The higher the confidence level, the narrower is the confidence interval for the mean. Select an answer The most efficient point estimator for the population mean ù is the sample median . Select an answer • To reduce the width of a confidence interval, we can increase the sample size n. Select an answer • As long as the population is normal with variance o’, the statistic (n-1) S2 has a Chi-squared 02 distribution with n degrees...
Please Help I need the answers to below. Question 2: Construct a 95% confidence interval for the population mean. Assume that your data is normally distributed and σ is unknown. Include a statement that correctly interprets the confidence interval in context of the scenario. Calculations/Values Formulas/Answers Mean 72,224.34 Standard Deviation 22,644.46 n 364 Critical Value Margin of Error Lower Limit Upper Limit Question 3 construct a 99% confidence interval for the population mean. Assume that your data is normally distributed...
Use the t-distribution to find a confidence interval for a difference in means u 1 - u 2 given the relevant sample results. Give the best estimate for u 1 - u 2, the margin of error, and the confidence interval. Assume the results come from random samples from populations that are approximately normally distributed. A 99% confidence interval for u 1 - u 2 using the sample results x 1 = 550, s 1 = 112, n 1 =...
Question 1 to 11, True or False? Applied business statistics
1) The width of the confidence interval depends only on the desired level of confidence 2) When population standard deviation is unknown, sample standaird deviation is used and the interval estimation is based on values from the t- rather than the z-distribution n 3) The z value for a 98% confidence interval around the point estimate is 2.33 4) In order to construct a 90% confidence interval for the population...
6.4.9-T Question Help Use technology to construct the confidence intervals for the population variance o? and the population standard deviation o. Assume the sample is taken from a normally distributed population. c=0.98, s2 = 4.41, n = 27 The confidence interval for the population variance is (Round to two decimal places as needed.) Enter your answer in the edit fields and then click Check Answer. 1 part remaining Clear All Check Answer
6.2.36-1 Question Help Use the standard normal distribution or the t-distribution to construct a 95% confidence interval for the population mean. Justify your decision. If neither distribution can be used, explain why. Interpret the results. In a random sample of 15 mortgage institutions, the mean interest rate was 3.42% and the standard deviation was 0.44%. Assume the interest rates are normally distributed Which distribution should be used to construct the confidence interval? O O O O O A. Use a...
a) Use the t-distribution to find a confidence interval for a difference in means μ1-μ2 given the relevant sample results. Give the best estimate for μ1-μ2, the margin of error, and the confidence interval. Assume the results come from random samples from populations that are approximately normally distributed. A 90% confidence interval for μ1-μ2 using the sample results x¯1=8.8, s1=2.7, n1=50 and x¯2=13.3, s2=6.0, n2=50 Enter the exact answer for the best estimate and round your answers for the margin...
1. The professor of statistics wants to estimate a confidence interval of 95% for some notes that are normally distributed with means of 74.2 and a standard deviation of 30.9 in a group of 30 students. Determine the interval corresponding to 95%. 2. Determine the limits (lower and upper) for a confidence interval of 68.26% for μ, given n = 64 x¯ = 118 and σ = 8. 3. Which is the dependent and independent variable? -advertising expenses -income by...