Question

A researcher wishes to​ estimate, with 9999​% ​confidence, the proportion of adults who have​ high-speed Internet access. Her estimate must be accurate within 44​% of the true proportion. ​a) Find the minimum sample size​ needed, using a prior study that found that 4242​% of the respondents said they have​ high-speed Internet access. ​b) No preliminary estimate is available. Find the minimum sample size needed. ​a) What is the minimum sample size needed using a prior study that found that 4242​% of the respondents said they have​ high-speed Internet​ access? nequals=nothing ​(Round up to the nearest whole number as​ needed.)

Answer 1

- Solutions Sin From 2-table] L 0.01 - (00 Honor From given data Margin of error (E) = 0.04 99.7. confidence interval eritical value Zdle = Zool = 70.005 = 2.576 fid=l-Confidencē Q.) I col-0.99 I P = 42 y. P= 42xóc P= 0.42 Sample size (n) = PCI-P) (ne = 014201–0:42)( 25.76 ) (n) = 1010.29 Sample size cm) - 11010 bi) Assume p=0.5 Sample size (n)= PCI-P)() LM) = 0.5(1-0.5)( 205026 ) (N) = 1036.84 sample size (m) 21037