Question

Write a Step by Step. Typed preferred.

(a) Oil of density 890 kg/m is stored in a tank with a triangular gate as shown in the side and front elevations in Figure Q2. The tank is full. Calculate: (i) the vertical height of the gate [2 marks] (ii) the hydrostatic force on the triangular gate [4 marks] (iii) the depth to the centre of pressure of the gate [8 marks] 400 SIDE VIEW FRONT VIEW

Answer 1

У = 10ws heG= 2.98 m Acp = 2.991 intech = 2.99m A 10.96m=h bakom vertical height of the h = 1.5 Sin 40 = 0.98m gate.

0 3.46 (a+105) = sin 400 x = 3.88m 12.540.96 2 2400 = 3.46on The centroidal depth of the gate is hea = (3.88 + 15) sin 40 = 2.98m from top Hydrostatic force on the triangular gate F = 81 XheGf Agate

= 890 x 2.98* *15*0.96) = 1909.584 uge = 1909.58489.81 - 18782 N moment of inential of the gate about x-a 122. = To = b = 158096° 0.036864 m'y

of pressure Depth her the centre of the for sino & hea = 0.036864 x Sin you f 2.98 + x1.5x0.9642.98 = 2.99 m. from top surface.