Question

A supervisor in a manufacturing plant has three men and three women working for him. He wants to choose four workers for a special job. Not wishing to show biases in his selection, he decides to select the four workers at random. Let Y denote the number of women in his selection. What is the probability that he selects two women?

Write your answer to one decimal place. e.g. 1.5, 0.2 etc.

Answer 1

Solution : There are N= 6 workers in which n = 3 mens n = 3 womens (init nga N26) The supervisor decides to select 1:4 wookers Y: The number of women in selection then What is probability that he selects two women ? ise PCY=2) 9 The total to cut possible outcomes of selecting 4 workers at random from 6 is - 15 and The total possible outcomes of selecting 4 workers at random from 6 in which 2 mme women is - Son 302 3*3 = 9 (2 from wo (2 from men Hence. The probability that the supervisor selects two women is P (Y=2) = 9 = 0.6 15 (22) = 0.6 for above problem is The general formula PCY = y) = Cnry (rey * = 3 3 * 15 Don on I PCY=2) = 0.6