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1. Consider an urn with 4 blue balls, 6 red balls, and 3 yellow balls. Suppose we draw 4 balls at random. (a) How many elemen
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1. a) There are a blue balls, & red talis 3 yellow boks . :. Total elements or balls in the затра зраас ога (4+6+3) = 12, b)9so is, required probability (3) (3) + 1303) 16 4x314x], - 15

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